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Probability Calculator

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Determine standard probability distributions, independent events ratios, and display interactive Venn diagrams.
Two Events
Normal PDF
Probability Output
Intersection: P(A ∩ B)
0.2000
Venn Diagram (Event Intersection)

Probability is the mathematical framework for quantifying uncertainty, risk, and the likelihood of future events. From determining the odds of compound events in gaming and insurance to evaluating statistical significance and Gaussian distributions in machine learning, probability rules provide the analytical bedrock for rational decision-making. Use this Probability Calculator to compute joint unions, intersections, complements, conditional probabilities, and continuous normal distribution $Z$-scores with instantaneous mathematical precision.

Core Probability Rules & Formula Quick Reference

Addition Rule (General Union)
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Multiplication Rule (Independent)
P(A ∩ B) = P(A) × P(B)
Complement Rule
P(A′) = 1 − P(A)
Standard Normal Z-Score
Z = (x − μ) / σ

1. Fundamental Principles of Probability Theory

In formal probability theory formulated by Andrey Kolmogorov, the probability of an event $A$, denoted as $P(A)$, satisfies three non-negotiable axioms:

  • Non-Negativity: For any event $A$, $0 \le P(A) \le 1$. Probability cannot be negative, nor can it exceed 100%.
  • Certainty of Sample Space: The probability of the entire sample space $S$ is exactly 1 ($P(S) = 1$). An outcome within $S$ is guaranteed to occur.
  • Countable Additivity: For any sequence of mutually disjoint (mutually exclusive) events $A_1, A_2, \dots$, the probability of their union equals the sum of their individual probabilities: $P(\bigcup A_i) = \sum P(A_i)$.

When working with discrete classical events where each elementary outcome in sample space $S$ is equally likely (such as rolling dice with a Dice Probability Calculator or flipping coins with a Coin Flip Probability Calculator), probability is computed as:

P(A) = n(E) / n(S) = (Number of Favorable Outcomes) / (Total Number of Possible Outcomes in Sample Space)

2. Two Events Relationships: Unions, Intersections & Conditions

When analyzing two distinct events $A$ and $B$, their interaction is governed by set theory operations visualized on a Venn diagram:

Operation / Metric Notation Independent Formula Venn Diagram Description
Union (“A OR B”) P(A ∪ B) P(A) + P(B) − [P(A) × P(B)] Area inside circle A, circle B, or both combined
Intersection (“A AND B”) P(A ∩ B) P(A) × P(B) Overlapping central football-shaped region
Complement of A (“NOT A”) P(A′) 1 − P(A) All area outside circle A
Exclusive OR (“XOR”) P(A ⊕ B) P(A ∪ B) − P(A ∩ B) Only A or only B, excluding the overlap
Neither Event Occurs P(A′ ∩ B′) 1 − P(A ∪ B) Exterior white space inside sample box
Conditional (“A Given B”) P(A|B) P(A ∩ B) / P(B) Ratio of intersection to entire circle B

3. Continuous Probability: The Normal (Gaussian) Distribution

In continuous probability distributions, variables take on infinite real values (e.g., human heights, test scores, stock returns). The Normal Distribution $\mathcal{N}(\mu, \sigma^2)$ is defined by its Probability Density Function (PDF):

f(x) = (1 / [σ√(2π)]) × exp( -0.5 × [(x – μ) / σ]² )

To find the probability that a value falls below a boundary $x$, we compute the standard score ($Z$-score) and evaluate the Cumulative Distribution Function ($\Phi(Z)$):

  • Z-Score Standardization: $Z = \frac{x – \mu}{\sigma}$, measuring how many standard deviations $x$ deviates from mean $\mu$.
  • Left-Tail Cumulative Area $P(X \le x)$: $\Phi(Z) = \int_{-\infty}^{Z} \frac{1}{\sqrt{2\pi}} e^{-t^2/2} dt$.
  • Right-Tail Area $P(X \ge x)$: $1 – \Phi(Z)$.

Standard Normal Z-Score & Confidence Interval Table

Z-Score ($Z$) Left-Tail Area $P(X \le x)$ Right-Tail Area $P(X \ge x)$ Two-Tailed Range $[\mu \pm Z\sigma]$ Statistical Significance
-3.00 0.00135 (0.135%) 0.99865 (99.865%) 99.73% Empirical Bound Extreme Outlier (3σ)
-1.96 0.02500 (2.500%) 0.97500 (97.500%) 95.00% Confidence Interval p < 0.05 Critical Threshold
-1.00 0.15866 (15.866%) 0.84134 (84.134%) 68.27% Empirical Bound 1 Standard Deviation Below
0.00 0.50000 (50.000%) 0.50000 (50.000%) 0.00% (Median) Mean / Median Center
+1.00 0.84134 (84.134%) 0.15866 (15.866%) 68.27% Empirical Bound 1 Standard Deviation Above
+1.96 0.97500 (97.500%) 0.02500 (2.500%) 95.00% Confidence Interval Standard 95% Confidence Upper
+2.58 0.99506 (99.506%) 0.00494 (0.494%) 99.00% Confidence Interval p < 0.01 Critical Threshold
+3.00 0.99865 (99.865%) 0.00135 (0.135%) 99.73% Empirical Bound 3-Sigma Quality Control

4. Reference Probability Benchmarks: Dice, Cards & Coin Flips

Use these standardized reference matrices to verify combinatorial probabilities for common randomized trials:

Two 6-Sided Dice Roll Sums

Target Sum Ways (out of 36) Probability
Sum = 2 or 12 1 / 36 2.78%
Sum = 3 or 11 2 / 36 5.56%
Sum = 4 or 10 3 / 36 8.33%
Sum = 5 or 9 4 / 36 11.11%
Sum = 6 or 8 5 / 36 13.89%
Sum = 7 (Most Likely) 6 / 36 16.67%

Standard 52-Card Deck Draws

Draw Event Count Probability
Specific Card (e.g., Ace of Spades) 1 / 52 1.92%
Any Ace (4 Aces) 4 / 52 = 1/13 7.69%
Face Card (J, Q, K) 12 / 52 = 3/13 23.08%
Specific Suit (e.g., Hearts) 13 / 52 = 1/4 25.00%
Specific Color (Red or Black) 26 / 52 = 1/2 50.00%
Non-Face Card (Numbered 2-10) 36 / 52 = 9/13 69.23%

5. Step-by-Step Worked Calculation Examples

Example 1: Computing Union & Intersection for Independent Events

Scenario: Event $A$ has a probability of $P(A) = 0.60$ and independent Event $B$ has a probability of $P(B) = 0.40$. Calculate $P(A \cap B)$, $P(A \cup B)$, and $P(A \oplus B)$ (Exclusive OR).

1. Intersection: $P(A \cap B) = P(A) \times P(B) = 0.60 \times 0.40 = \mathbf{0.24}$ (or $24.0\%$)
2. Union: $P(A \cup B) = P(A) + P(B) – P(A \cap B) = 0.60 + 0.40 – 0.24 = \mathbf{0.76}$ (or $76.0\%$)
3. Exclusive OR: $P(A \oplus B) = P(A \cup B) – P(A \cap B) = 0.76 – 0.24 = \mathbf{0.52}$ (or $52.0\%$)
4. Neither Event Occurs: $P(\text{Neither}) = 1 – P(A \cup B) = 1 – 0.76 = \mathbf{0.24}$ (or $24.0\%$)

Example 2: Continuous Normal Distribution & Percentile Rank

Scenario: A university entrance exam has a normally distributed mean score of $\mu = 500$ with a standard deviation of $\sigma = 100$. What is the probability that a randomly chosen student scores $650$ or higher ($P(X \ge 650)$)?

1. Calculate Z-Score: $Z = \frac{x – \mu}{\sigma} = \frac{650 – 500}{100} = \frac{150}{100} = \mathbf{+1.50}$
2. Cumulative Left-Tail Probability: $\Phi(1.50) = 0.93319$ ($93.32\%$ score 650 or lower)
3. Right-Tail Probability ($X \ge 650$): $P(X \ge 650) = 1 – 0.93319 = \mathbf{0.06681}$ (or $\mathbf{6.68\%}$)
Interpretation: Only $6.68\%$ of examinees score $650$ or higher, placing a student scoring 650 in the 93.3rd percentile.